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What is the purpose of a heat sink or heat spreader?

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I am trying to convince my electrical engineers that a heat sink or heat spreader is important to cool their hot CPU's.  Can someone give me some help on how they work so I can prove it?
asked Dec 4, 2014 by joday (340 points)

3 Answers

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In electronic systems, a heat sink is a passive component that cools a device by dissipating heat into the surrounding air. Heat sinks are used to cool electronic components such as high-power semiconductor devices, and optoelectronic devices such as higher-power lasers and light emitting diodes (LEDs). Heat sinks are heat exchangers such as those used in refrigeration and air conditioning systems, or the radiator in an automobile.

answered Dec 4, 2014 by joday (340 points)
0 votes

  You may also want to give your colleagues some information relative to basic heat transfer principles to help them better understand. 

A heat sink is an object that transfers thermal energy from a higher temperature to a lower temperature fluid medium. The fluid medium is frequently air, but can also be water or in the case of heat exchangers, refrigerants and oil. If the fluid medium is water, the 'heat sink' is frequently called a cold plate. In thermodynamics a heat sink is a heat reservoir that can absorb an arbitrary amount of heat without significantly changing temperature. Practical heat sinks for electronic devices must have a temperature higher than the surroundings to transfer heat by convection, radiation, and conduction.

To understand the principle of a heat sink, consider Fourier's law of heat conduction. Joseph Fourier was a French mathematician who made important contributions to the analytical treatment of heat conduction.[1] Fourier's law of heat conduction, simplified to a one-dimensional form in the x-direction, shows that when there is a temperature gradient in a body, heat will be transferred from the higher temperature region to the lower temperature region. The rate at which heat is transferred by conduction, q_k, is proportional to the product of the temperature gradient and the cross-sectional area through which heat is transferred

answered Dec 4, 2014 by joday (340 points)
0 votes

Here is a video to help them answer:

answered Dec 4, 2014 by joday (340 points)
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